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Does .9999999… = 1?

February 19th, 2007 · 1 Comment

Apparently there is a lot of discussion out there as to the validity of this statement. The main argument for equality goes something like this. Say x = 0.99999… (or commonly expressed as .9). Multiply both sides by 10 and you have 2 equations that you can subtract from each other.

 10x = 9.9999999...
-  x = 0.9999999...
-------------------
  9x = 9

Reduce the result and now you have x = 1, but as we expressed earlier, x = 0.99999, so 0.99999… = 1. Simple enough, right?

Check out all of the discussion here, here, and and some false counter-examples here.

Tags: Math

1 response so far ↓

  • 1 donnie // Feb 22, 2007 at 8:06 pm

    That’s a good easy to understand proof. I heard it as the limit of an infinite series: sum_(n=1->oo) 9/10^n which is just about as easy to understand as it is to write in ascii.

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